CodeForces 658A Bear and Reverse Radewoosh

最新推荐文章于 2022-08-24 17:07:02 发布

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本文概述了AI音视频处理领域的关键技术，包括视频分割、语义识别、自动驾驶、AR、SLAM等，并探讨了其在实际应用中的作用。

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思路：水题，直接扫两遍就好了

#include <cstdio>
#include <queue>
#include <cstring>
#include <iostream>
#include <cstdlib>
#include <algorithm>
#include <vector>
#include <map>
#include <string>
#include <set>
#include <ctime>
#include <cmath>
#include <cctype>
using namespace std;
#define maxn 100
#define LL long long
int cas=1,T;
LL p[maxn];
LL t[maxn];
int main()
{
	int n,c;
	scanf("%d%d",&n,&c);
	for (int i = 1;i<=n;i++)
		scanf("%lld",&p[i]);
	for (int i = 1;i<=n;i++)
		scanf("%lld",&t[i]);
	LL p1=0,p2=0;
	LL sum = 0;
	for (int i = 1;i<=n;i++)
	{
		sum+=t[i];
		p1+=max(0LL,p[i]-c*sum);
	}
	sum = 0;
	for (int i = n;i>=1;i--)
	{
		sum+=t[i];
		p2+=max(0LL,p[i]-c*sum);
	}
	if (p1>p2)
		printf("Limak\n");
	else if (p2>p1)
		printf("Radewoosh\n");
	else
		printf("Tie\n");
	//freopen("in","r",stdin);
	//scanf("%d",&T);
	//printf("time=%.3lf",(double)clock()/CLOCKS_PER_SEC);
	return 0;
}

Description

Limak and Radewoosh are going to compete against each other in the upcoming algorithmic contest. They are equally skilled but they won't solve problems in the same order.

There will be n problems. The i-th problem has initial score p_i and it takes exactly t_i minutes to solve it. Problems are sorted by difficulty — it's guaranteed that p_i < p_i + 1 and t_i < t_i + 1.

A constant c is given too, representing the speed of loosing points. Then, submitting the i-th problem at time x (x minutes after the start of the contest) gives max(0, p_i - c·x) points.

Limak is going to solve problems in order 1, 2, ..., n (sorted increasingly by p_i). Radewoosh is going to solve them in order n, n - 1, ..., 1 (sorted decreasingly by p_i). Your task is to predict the outcome — print the name of the winner (person who gets more points at the end) or a word "Tie" in case of a tie.

You may assume that the duration of the competition is greater or equal than the sum of all t_i. That means both Limak and Radewoosh will accept all n problems.

Input

The first line contains two integers n and c (1 ≤ n ≤ 50, 1 ≤ c ≤ 1000) — the number of problems and the constant representing the speed of loosing points.

The second line contains n integers p₁, p₂, ..., p_n (1 ≤ p_i ≤ 1000, p_i < p_i + 1) — initial scores.

The third line contains n integers t₁, t₂, ..., t_n (1 ≤ t_i ≤ 1000, t_i < t_i + 1) where t_i denotes the number of minutes one needs to solve the i-th problem.

Output

Print "Limak" (without quotes) if Limak will get more points in total. Print "Radewoosh" (without quotes) if Radewoosh will get more points in total. Print "Tie" (without quotes) if Limak and Radewoosh will get the same total number of points.

Sample Input

Input

3 2
50 85 250
10 15 25

Output

Limak

Input

3 6
50 85 250
10 15 25

Output

Radewoosh

Input

8 1
10 20 30 40 50 60 70 80
8 10 58 63 71 72 75 76

Output

Tie