Description
Given a set of sticks of various lengths, is it possible to join them end-to-end to form a square?
Input
The first line of input contains N, the number of test cases. Each test case begins with an integer 4 <= M <= 20, the number of sticks. M integers follow; each gives the length of a stick - an integer between 1 and 10,000.
Output
For each case, output a line containing "yes" if is is possible to form a square; otherwise output "no".
Sample Input
3 4 1 1 1 1 5 10 20 30 40 50 8 1 7 2 6 4 4 3 5
Sample Output
yes no yes#include<iostream> #include<cstdio> #include<cstring> #include<algorithm> using namespace std; int a[25]; int vis[25]; int n,sum; int dfs(int d, int w, int cnt) { if(d == sum) { w = 0; d = 0; cnt++; if(cnt == 4) return 1; } for(int i=w; i<n; i++) { if(!vis[i]) { vis[i] = 1; if((d+a[i] <= sum ) && dfs(d+a[i], i+1, cnt)) return 1; vis[i] = 0; } } return 0; } int main() { int T; cin>>T; while(T--) { cin>>n; sum = 0; memset(vis, 0, sizeof(vis)); memset(a, 0, sizeof(a)); for(int i=0; i<n; i++) { cin>>a[i]; sum += a[i]; } int flag = 0; if(sum % 4 ==0) { sum /= 4; flag = dfs(0, 0, 0); } if(flag) { cout<<"yes"<<endl; } else { cout<<"no"<<endl; } } }