不用临时变量实现两个变量的交换-C++

#include <iostream>
using namespace std;
 
void Switch(int *p1, int *p2) {
	*p1 = *p1 + *p2;
	*p2 = *p1 - *p2;
	*p1 = *p1 - *p2;
}
void Xor(int *p1, int *p2) {
	*p1 = *p1^*p2;//异或操作
	*p2 = *p1^*p2;
	*p1 = *p1^*p2;
}
int main() {
	int a = 1,b = 2;
	int *p1 = &a;
	int *p2 = &b;
	cout << "p1:" << *p1 << endl;
	cout << "p2:" << *p2 << endl;

	Switch(p1,p2);
	cout << "p1:" << *p1 << endl;
	cout << "p2:" << *p2 << endl;

	Xor(p1, p2);
	cout << "p1:" << *p1 << endl;
	cout << "p2:" << *p2 << endl;
}

方法一有缺陷：相加和可能存在溢出情况