osigmao的专栏

//二分搜索 //考虑溢出的情况,所以要用long！要通过编译的话，还要强制类型转换回来！ public class Solution {     public int sqrt(int x) {         if (x         long beg = 1;         long end = x/2;                  while (beg    

两次二分 public class Solution { public int[] searchRange(int[] A, int target) { int[] res = new int[2]; res[0] = -1; res[1] = -1; int beg = 0; in