//求n的阶乘
/*
#include<stdio.h>
int count_n(int n)
{
int m = 0;
int sum = n;
for(m=1;m<n;m++)
{
sum=sum*m;
}
return sum;
}
//用递归求n的阶乘
int count_n1(int n)
{
if(n>1)
{
return count_n1(n-1)*n;
}
else
{
return 1;
}
}
int main()
{
int n = 0;
int sum = 0;
scanf("%d",&n);
sum = count_n1(n);
printf("%d",sum);
return 0;
}
*/
//将数组逆序排列
/*
#include<stdio.h>
#include<string.h>
void reverse_string(char* arr,int sz)
{
int left = 0;
int right = sz-2;// 不能写sz-1,因为会把\0也交换,导致结果显示为0;
while(left<right)
{
char tem = arr[left];
arr[left] = arr[right];
arr[right] = tem;
left++;
right--;
}
}
void reverse_string1(char* arr1)
{
int left = 0;
int right = strlen(arr1)-1;//???为什么能用strlen不能用int sz = sizeof(arr)/sizeof(arr[0])在函数里求;
while(left<right)
{
char tem = arr1[left];
arr1[left] = arr1[right];
arr1[right] = tem;
left++;
right--;
}
}
void reverse_string2(char* arr,int sz)
{
int left = 0;
int right = sz-2;// 不能写sz-1,因为会把\0也交换,导致结果显示为0;
while(left<right)
{
char tem = *(arr+left);
*(arr+left) = *(arr+right);
*(arr+right) = tem;
left++;
right--;
}
}
int my_strlen(int* arr)
{
int count = 0;
while(*arr != 0)
{
count++;
arr++;
}
return count;
}
int main()
{
char arr[] = "abcdef";
int sz = sizeof(arr)/sizeof(arr[0]);
reverse_string(arr,sz);
printf("%s\n",arr);
return 0;
}
*/
//用递归的方法将数组逆序
/*
int my_strlen(char* arr)
{
int count = 0;
while(*arr != 0)
{
count++;
arr++;
}
return count;
}
void reverse_string0(char* arr)
{
int len=my_strlen(arr);
char tem = arr[0];
arr[0]=arr[len-1];
arr[len-1] = '\0';
if(my_strlen(arr)>=2)//写成if(my_strlen(arr+1)>=2)也没问题,??为什么
reverse_string0(arr+1);
arr[len-1] = tem;
}
#include<stdio.h>
int main()
{
char arr[] = "abcd";
reverse_string0(arr);
printf("%s\n",arr);
return 0;
}
*/
//结构体
//struct 结构体关键字 stu 结构体标签 struct stu - 结构体类型
/*
struct stu
{
char name[20];
short age;
char tele[12];
char sex[5];
}s1,s2,s3;//s1,s2,s3是三个全局的结构体变量
typedef struct stu
{
char name[20];
short age;
char tele[12];
char sex[5];
}stu;
int main()
{
struct stu s1;//局部变量.
stu s2;
return 0;
}
*/
/*
#include<stdio.h>
struct s
{
int a;
char c;
char arr[20];
double d;
};
struct t
{
char ch[10];
struct s s;
char* pc;
};
int main()
{
char arr[] = "hello bit\n";
struct t t = {"hehe",{100,'w',"hello world",3.14},arr};
printf("%s\n",t.ch);//hehe
printf("%s\n",t.s.arr);//hello world
printf("%lf\n",t.s.d);//3.14
printf("%s\n",t.pc);//hello bit
return 0;
}
*/
题目和结构体初步认识
最新推荐文章于 2024-12-07 21:12:48 发布