Bob Evans在应用中发现Fixnum#sort并不使用 <=>操作符,代码如下: class Fixnum @@count = 0 alias originalComparator <=> def <=>(o) @@count += 1 originalComparator(o) end def Fixnum.count @@count end end Running against it: >array = [5, 4, 3, 2, 1] => [5,4,3,2,1] >array.sort => [1,2,3,4,5] >Integer.count => 0 Expected => 6 > result > 0 实际正是如此,这可以从Ruby的源代码中看出: $ cd /v/build/ruby/ruby-1.8.1-2004.05.02/ $ less array.c static int sort_2(ap, bp) ... if (FIXNUM_P(a) && FIXNUM_P(b)) { if (a > b) return 1; if (a < b) return -1; return 0; } if (TYPE(a) == T_STRING && TYPE(b) == T_STRING) { return rb_str_cmp(a, b); } ... static VALUE sort_internal(ary) VALUE ary; { qsort(RARRAY(ary)->ptr, RARRAY(ary)->len, sizeof(VALUE), rb_block_given_p()?sort_1:sort_2); return ary; } 可见,Ruby确实没有使用<=>,而用最一般的 >,
[Ruby-talk]对Fixnum与的讨论
最新推荐文章于 2025-04-10 18:37:10 发布