10055-Hashmat the Brave Warrior

最新推荐文章于 2014-07-07 19:41:50 发布

原创最新推荐文章于 2014-07-07 19:41:50 发布 · 696 阅读

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Hashmat是一位勇敢的战士，他和他的年轻士兵们从一个地方移动到另一个地方与对手作战。在战斗前，他仅计算自己士兵数量与对手士兵数量之间的差异来决定是否参与战斗，且他的士兵数量永远不会超过对手。

Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.

Input

The input contains two integer numbers in every line. These two numbers in each line denotes the number of soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers arenot greater than 2^32. Input is terminated by End of File.

Output

For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in seperate line.

Sample Input:

10 12

10 14

100 200

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KEY：not greater than 2^32，人数默认>=0, 而int的最大范围是-2的15次方~2的15次方-1, 范围过小不满足题目要求，故使用unsigned long或unsigned int

#include <iostream>

using namespace std;

int main(void)
{
unsigned long a,b;
while (cin >>a >>b)
{
  a>b? cout <<a-b <<endl : cout << b-a <<endl;
}
return 0;
}