10055 - Hashmat the Brave Warrior

Hashmat是一位勇敢的战士,带着一群年轻士兵从一个战场转移到另一个战场,与对手战斗。他通过计算自己士兵数量与对手数量之差来决定是否战斗。本文详细介绍了输入和输出规则,并提供了一个示例输入输出,帮助理解如何解决这个问题。

Hashmat the brave warrior

Input: standard input

Output: standard output

 

Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.


Input

The input contains two integer numbers in every line. These two numbers in each line denotes the number of soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2^32. Input is terminated by End of File.

 

Output

 For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in seperate line.

 

Sample Input:

10 12
10 14
100 200

 

Sample Output:

2
4
100
___________________________________________________________________________________ 
Shahriar Manzoor

16-12-2000

___________________________________________________________________________________ 

#include<stdio.h>

int main()
{
long long int a, b;

while (scanf("%lld%lld", &a, &b) != EOF)
printf("%lld\n", a > b ? a - b : b - a);
return 0;
}

___________________________________________________________________________________ 

这个题需要注意的有,Sample Input是来做参考的,输出要注意的东西并未表达完.看题要仔细,Hashmat的人数和敌人的人数的顺序不定.还有注意数据范围!

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