Given two strings s and t, determine if they are isomorphic.
Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
For example,
Given "egg"
, "add"
,
return true.
Given "foo"
, "bar"
,
return false.
Given "paper"
, "title"
,
return true.
Note:
You may assume both s and t have the same length.
注意用例"ab","aa"。
public boolean isIsomorphic(String s, String t) {
if (s.length() != t.length()) return false;
HashMap<Character, Integer> mapS = new HashMap<Character, Integer>();
HashMap<Character, Integer> mapT = new HashMap<Character, Integer>();
for (int i = 0; i < s.length(); i++) {
if (!mapS.containsKey(s.charAt(i)))
mapS.put(s.charAt(i), s.charAt(i) - t.charAt(i));
if (!mapT.containsKey(t.charAt(i)))
mapT.put(t.charAt(i), s.charAt(i) - t.charAt(i));
if (mapS.get(s.charAt(i)) != s.charAt(i) - t.charAt(i)) return false;
if (mapT.get(t.charAt(i)) != s.charAt(i) - t.charAt(i)) return false;
}
return true;
}