单晶塑性abaqus-umat 自学
本文以翻译黄永刚老师的umat文章为主, 这个颜色的为补充材料和个人的理解。
摘要
包含单晶塑性的abaqus用户材料子程序。本文回顾有限元形式的单晶弹塑性和黏弹塑性,包含小变形理论,以及严格的有限变形和有限旋转理论。单晶的非弹性变形由于晶体滑移,假定遵从Schmid准则。提出多种多样的分切应力与剪切变形的自硬化和潜硬化关系,并且包含在子程序内。
1. 简介
有限元程序ABAQUS已经广泛应用在固体的变形与应力分析。除了自身大量的本构模型,ABAQUS还提供用户子程序接口。应力、应变以及求解依赖的状态变量以增量形式求出。当umat子程序被访问时,提供增量步开始的状态(应力以及求解依赖的状态变量)和应变和时间增量。umat子程序执行二段程序:更新应力和状态变量使其等于增量步结束时对应的值,提供材料的Jacobian矩阵, ∂ Δ σ / ∂ Δ ε \partial \Delta\sigma/\partial \Delta\varepsilon ∂Δσ/∂Δε,为Newton-Rhapson迭代提供相应的本构模型。
本文的主要目标是提供单晶塑性的本构的框架。运动学部分严格满足有限变形。塑性变形仅仅考虑位错滑移,不考虑扩散变形,孪晶和晶界滑移。Schmid应力,或滑移系上分切应力假定是滑移的驱动力。完整的子程序用于单晶和双晶的变形和断裂分析。
2. 单晶弹塑性本构模型回顾
2.1运动学
晶体力学的运动学理论的先驱是Taylor(1938),精准的力学理论是Hill(1966),Rice(1971)和Hill and Rice(1972)搭建的。下面是关于Asaro and Rice(1977)和Asaro(1983)简单的理论总结。
晶体材料的弹性变形和旋转是由晶格承担的。单晶的非弹性变形源于晶体滑移。材料流动是通过位错在晶格上的运动。总的变形梯度 F \bm{F} F: F = F ∗ ⋅ F P \bm{F=F^*\cdot F^P} F=F∗⋅FP
其中 F P F^P FP 是中间构型的塑性剪切, F ∗ F^* F∗ 为晶格拉伸和旋转。假设弹性特征不受滑移的影响,应力由 F ∗ F^* F∗ 单独决定。 F P F^P FP 的变化率与 α \alpha α 滑移系的滑移率 γ ˙ ( α ) \dot{\gamma}^{(\alpha)} γ˙(α) 有关。
F P ˙ ⋅ F P − 1 ˙ = ∑ α γ ˙ ( α ) s ( α ) m ( α ) \dot{\bm{F}^P}\cdot\dot{\bm{F}^{P-1}}=\sum_{\alpha}\dot{\gamma}^{(\alpha)}{s}^{(\alpha)}{m}^{(\alpha)} FP˙⋅FP−1˙=α∑γ˙(α)s(α)m(α)
对所有激活的滑移系求和, s ( α ) {s}^{(\alpha)} s(α) 和 m ( α ) {m}^{(\alpha)} m(α) 分别是参考构型下滑移方向和滑移面的法向。
补充:单滑移变形梯度描述
速度梯度张量 L \bm L L
L = F ˙ ⋅ F − 1 = F ˙ ∗ ⋅ F P ⋅ F P − 1 ⋅ F ∗ − 1 + F ∗ ⋅ F ˙ P ⋅ F P − 1 ⋅ F ∗ − 1 = F ˙ ∗ ⋅ F ∗ − 1 + F ∗ ⋅ F ˙ P ⋅ F P − 1 ⋅ F ∗ − 1 \begin{aligned} \bm{L}&=\bm{\dot{F}}\cdot\bm{F^{-1}}=\bm{\dot F^*\cdot F^P}\cdot\bm{ F^{P-1}\cdot F^{*-1}}+\bm{ F^*\cdot \dot F^P}\cdot\bm{ F^{P-1}\cdot F^{*-1}}\\ &=\bm{\dot F^*}\cdot\bm{ F^{*-1}}+\bm{ F^*\cdot \dot F^P}\cdot\bm{ F^{P-1}\cdot F^{*-1}}\\ \end{aligned} L=F˙⋅F−1=F˙∗⋅FP⋅FP−1⋅F∗−1+F∗⋅F˙P⋅FP−1⋅F∗−1=F˙∗⋅F∗−1+F∗⋅F˙P⋅FP−1⋅F∗−1
求 F P − 1 \bm{ F^{P-1}} FP−1 由于:
[ I − γ ( α ) s ( α ) m ( α ) ] ⋅ [ I + γ ( α ) s ( α ) m ( α ) ] = I − γ ( α ) 2 s ( α ) m ( α ) ⋅ s ( α ) m ( α ) \begin{aligned} &[\bm{I}-{\gamma}^{(\alpha)}{s}^{(\alpha)}{m}^{(\alpha)}]\cdot[\bm{I}+{\gamma}^{(\alpha)}{s}^{(\alpha)}{m}^{(\alpha)}]\\\quad\\ =&\bm{I}-{\gamma}^{(\alpha)^2}{s}^{(\alpha)}{m}^{(\alpha)}\cdot{s}^{(\alpha)}{m}^{(\alpha)} \end{aligned} =[I−γ(α)s(α)m(α)]⋅[I+γ(α)s(α)m(α)]I−γ(α)2s(α)m(α)⋅s(α)m(α)
滑移方向和滑移面法向垂直: m ( α ) ⋅ s ( α ) = 0 {m}^{(\alpha)}\cdot{s}^{(\alpha)}=0 m(α)⋅s(α)=0
因此: F P − 1 = I − γ ( α ) s ( α ) m ( α ) \bm{ F^{P-1}}=\bm{I}-{\gamma}^{(\alpha)}{s}^{(\alpha)}{m}^{(\alpha)} FP−1=I−γ(α)s(α)m(α)
F P ˙ ⋅ F P − 1 = [ γ ˙ ( α ) s ( α ) m ( α ) ] ⋅ [ I − γ ( α ) s ( α ) m ( α ) ] = γ ˙ ( α ) s ( α ) m ( α ) \bm{ \dot{F^P} \cdot F^{P-1}}=[\dot{\gamma}^{(\alpha)}{s}^{(\alpha)}{m}^{(\alpha)}]\cdot[\bm{I}-{\gamma}^{(\alpha)}{s}^{(\alpha)}{m}^{(\alpha)}]=\dot{\gamma}^{(\alpha)}{s}^{(\alpha)}{m}^{(\alpha)} FP˙⋅FP−1=[γ˙(α)s(α)m(α)]⋅[I−γ(α)s(α)m(α)]=γ˙(α)s(α)m(α)
为了方便定义 s ∗ ( α ) s^{*(\alpha)} s∗(α) 为 α \alpha α 滑移系在变形后的构型中的滑移方向:
s ∗ ( α ) = F ∗ ⋅ s ( α ) s^{*(\alpha)}=F^* \cdot s^{(\alpha)} s∗(α)=F∗⋅s(α)
定义 m ∗ ( α ) m^{*(\alpha)} m∗(α) 为 α \alpha α 滑移系在变形后的构型中的滑移面的法向:
m ∗ ( α ) = m ( α ) ⋅ F ∗ − 1 m^{*(\alpha)}= m^{(\alpha)}\cdot F^{*-1} m∗(α)=m(α)⋅F∗−1
因此:
L = F ˙ ∗ ⋅ F ∗ − 1 + γ ˙ ( α ) F ∗ ⋅ s ( α ) m ( α ) ⋅ F ∗ − 1 = F ˙ ∗ ⋅ F ∗ − 1 + γ ˙ ( α ) s ∗ ( α ) m ∗ ( α ) = L ∗ + L P \begin{aligned} \bm{L}&=\bm{\dot F^*}\cdot\bm{ F^{*-1}}+\dot{\gamma}^{(\alpha)}\bm{ F^*\cdot }{s}^{(\alpha)}{m}^{(\alpha)}\bm{ \cdot F^{*-1}}\\\quad\\ &=\bm{\dot F^*}\cdot\bm{ F^{*-1}}+\dot{\gamma}^{(\alpha)}\bm{s}^{*(\alpha)}\bm{m}^{*(\alpha)}\\\quad\\ &=\bm{L^*}+\bm{L^P} \end{aligned} L=F˙∗⋅F∗−1+γ˙(α)F∗⋅s(α)m(α)⋅F∗−1=F˙∗⋅F∗−1+γ˙(α)s∗(α)m∗(α)=L∗+LP
当前状态的速度梯度矩阵:
L = F ˙ ⋅ F − 1 = D + Ω \bm{L}=\bm{\dot{F}\cdot F^{-1}}=\bm{D}+\bm{\Omega} L=F˙⋅F−1=D+Ω
其中, D D D 为对称的拉伸率, Ω \Omega Ω 为反对称的自旋张量。可分解为晶格部分(上标*)和塑性部分(上标P):
D = D ∗ + D P Ω = Ω ∗ + Ω P \bm{D=D^*+D^P}\quad \bm{\Omega=\Omega^*+\Omega^P} D=D∗+DPΩ=Ω∗+ΩP
满足: D ∗ + Ω ∗ = F ˙ ∗ ⋅ F ∗ − 1 D P + Ω P = ∑ α γ ˙ ( α ) s ∗ ( α ) m ∗ ( α ) \bm{D^*+\Omega^*}=\bm{\dot F^*}\cdot\bm{ F^{*-1}}\quad \bm{D^P+\Omega^P}=\sum_{\alpha}\dot{\gamma}^{(\alpha)}\bm{s}^{*(\alpha)}\bm{m}^{*(\alpha)} D∗+Ω∗=F˙∗⋅F∗−1DP+ΩP=α∑γ˙(α)s∗(α)m∗(α)
2.2 本构
依据 Hill and Rice(1972),存在弹性势能, Φ = Φ ( F ∗ ) \Phi=\Phi(F^*) Φ=Φ(F∗) ,保证对称的晶格变形率张量 D ∗ \bm{D^*} D∗, 和Cauchy应力的Jaumann客观应变率满足如下关系:
σ ∇ ∗ + σ ( I : D ∗ ) = L : D ∗ (2.2.1) \overset{\nabla}{\bm{\sigma}}^*+\bm{\sigma}\left( \bm{I:D^*}\right)=\bm{L:D^*}\tag{2.2.1} σ∇∗+σ(I:D∗)=L:D∗(2.2.1)
其中 I I I是二阶单位张量, L \bm{L} L 是弹性张量具有如下对称性 L i j k l = L j i k l = L i j l k = L k l i j L_{ijkl}=L_{jikl}=L_{ijlk}=L_{klij} Lijkl=Ljikl=Lijlk=Lklij,Jaumann率 σ ∇ ∗ \overset{\nabla}{\bm{\sigma}}^* σ∇∗ 是晶格坐标轴上的共转应力率,Jaumann率 σ ∇ \overset{\nabla}{\bm{\sigma}} σ∇ 是材料坐标轴上的共转应力率,二者之间的关系:
σ ∇ ∗ = σ ∇ + ( Ω − Ω ∗ ) ⋅ σ − σ ⋅ ( Ω − Ω ∗ ) (2.2.2) \overset{\nabla}{\bm{\sigma}}^*=\overset{\nabla}{\bm{\sigma}}+(\Omega-\Omega^*)\cdot \sigma- \sigma\cdot(\Omega-\Omega^*)\tag{2.2.2} σ∇∗=σ∇+(Ω−Ω∗)⋅σ−σ⋅(Ω−Ω∗)(2.2.2)
其中, σ ∇ = σ ˙ − Ω ⋅ σ + σ ⋅ Ω \overset{\nabla}{\bm{\sigma}}=\dot{\bm{\sigma}}-\Omega\cdot \sigma+\sigma\cdot\Omega σ∇=σ˙−Ω⋅σ+σ⋅Ω
补充:
在Lagrange坐标下,变形率 D ∗ D^* D∗ 和 Kirchhoff应力 τ ∗ = J σ ∗ \tau^*=J\sigma^* τ∗=Jσ∗ 共轭
τ ∇ ∗ = L : D ∗ \overset{\nabla}{\tau}^*=\bm{L:D^*} τ∇∗=L:D∗
其中:
τ ∇ ∗ = τ ∗ ˙ − Ω ⋅ τ ∗ + τ ∗ ⋅ Ω = J ˙ σ ∗ + J σ ∗ ˙ − J Ω ⋅ σ ∗ + J σ ∗ ⋅ Ω = J σ ∗ ( I : D ) + J σ ∗ ˙ − J Ω ⋅ σ ∗ + J σ ∗ ⋅ Ω = J [ σ ∗ ( I : D ) + σ ∗ ∇ ] \begin{aligned} \overset{\nabla}{\tau}^*&=\dot{\tau^*}-\Omega\cdot \tau^*+\tau^*\cdot\Omega\\ &=\dot{J}\sigma^*+J\dot{\sigma^*}-J\Omega\cdot \sigma^*+J\sigma^*\cdot\Omega\\ &=J\sigma^*({I:D})+J\dot{\sigma^*}-J\Omega\cdot \sigma^*+J\sigma^*\cdot\Omega\\ &=J\left[\sigma^*({I:D})+\overset{\nabla}{\sigma^*}\right] \end{aligned} τ∇∗=τ∗˙−Ω⋅τ∗+τ∗⋅Ω=J˙σ∗+Jσ∗˙−JΩ⋅σ∗+Jσ∗⋅Ω=Jσ∗(I:D)+Jσ∗˙−JΩ⋅σ∗+Jσ∗⋅Ω=J[σ∗(I:D)+σ∗∇]
考虑到从初始构型到中间构型只发生滑移,忽略体积变化 J = det F ≈ 1 J=\det{F}\approx 1 J=detF≈1
因此:
σ ∇ ∗ + σ ( I : D ∗ ) = L : D ∗ \overset{\nabla}{\bm{\sigma}}^*+\bm{\sigma}\left( \bm{I:D^*}\right)=\bm{L:D^*} σ∇∗+σ(I:D∗)=L:D∗
晶体滑移遵循Schmid准则,任意滑移系 α \alpha α的滑移率 γ ˙ ( α ) \dot{\gamma}^{(\alpha)} γ˙(α)假设只与当前应力 σ \sigma σ 的Schmid应力 τ ( α ) {\tau}^{(\alpha)} τ(α)。Schmid应力是忽略晶格畸变后的分切应力。Asaro and Rice(1977)讨论了现有有限弹性畸变的一些可能的一般化。本文基于Rice(1971),热力学应力与滑移共轭。定义:
τ ( α ) = m ∗ ( α ) ⋅ ρ 0 ρ σ ⋅ s ∗ ( α ) (2.2.3) \tau^{(\alpha)}=m^{*(\alpha)}\cdot\frac{\rho_0}{\rho}\sigma\cdot s^{*(\alpha)}\tag{2.2.3} τ(α)=m∗(α)⋅ρρ0σ⋅s∗(α)(2.2.3)
其中 ρ 0 {\rho_0} ρ0 和 ρ {\rho} ρ 参考构型和当前构型的密度;Hill and Rice(1972)认为 τ ( α ) \tau^{(\alpha)}\, τ(α)等于随晶格旋转的Kirchhoff应力的最大剪切分量。Schmid应力的变化率如下:
τ ˙ ( α ) = m ∗ ( α ) ⋅ [ σ ∇ ∗ + σ ( I : D ∗ ) − D ∗ ⋅ σ + σ ⋅ D ∗ ] ⋅ s ∗ ( α ) (2.2.4) \dot\tau^{(\alpha)}=m^{*(\alpha)}\cdot \left[ \overset{\nabla}{\bm{\sigma}}^*+\bm{\sigma}\left( \bm{I:D^*}\right)-\bm{D^*\cdot\sigma+\sigma\cdot D^*}\right]\cdot s^{*(\alpha)}\tag{2.2.4} τ˙(α)=m∗(α)⋅[σ∇∗+σ(I:D∗)−D∗⋅σ+σ⋅D∗]⋅s∗(α)(2.2.4)
补充:
式(2.2.3)中: ρ 0 ρ = d v d V = J \frac{\rho_0}{\rho}=\frac{dv}{dV}=J ρρ0=dVdv=J
因此:
τ ˙ ( α ) = m ˙ ∗ ( α ) ⋅ J σ ⋅ s ∗ ( α ) + m ∗ ( α ) ⋅ ( J σ ) ˙ ⋅ s ∗ ( α ) + m ∗ ( α ) ⋅ J σ ⋅ s ˙ ∗ ( α ) \dot\tau^{(\alpha)}=\dot m^{*(\alpha)}\cdot J\sigma\cdot s^{*(\alpha)}+m^{*(\alpha)}\cdot \dot{(J\sigma)}\cdot s^{*(\alpha)}+m^{*(\alpha)}\cdot J\sigma\cdot \dot s^{*(\alpha)} τ˙(α)=m˙∗(α)⋅Jσ⋅s∗(α)+m∗(α)⋅(Jσ)˙⋅s∗(α)+m∗(α)⋅Jσ⋅s˙∗(α)
其中:
m ∗ ( α ) ⋅ ( J σ ) ˙ ⋅ s ∗ ( α ) = m ∗ ( α ) ⋅ [ ( J σ ) ∇ + Ω ∗ ⋅ σ − σ ⋅ Ω ∗ ] ⋅ s ∗ ( α ) = m ∗ ( α ) ⋅ [ σ ∇ ∗ + σ ( I : D ∗ ) − Ω ∗ ⋅ σ + σ ⋅ Ω ∗ ] ⋅ s ∗ ( α ) \begin{aligned} m^{*(\alpha)}\cdot \dot{(J\sigma)}\cdot s^{*(\alpha)}&=m^{*(\alpha)}\cdot[ \overset{\nabla}{(J\sigma)}+\Omega^*\cdot \sigma- \sigma\cdot\Omega^*]\cdot s^{*(\alpha)}\\&=m^{*(\alpha)}\cdot[\overset{\nabla}{\bm{\sigma}}^*+\bm{\sigma}\left( \bm{I:D^*}\right)-\Omega^*\cdot \sigma+ \sigma\cdot\Omega^*]\cdot s^{*(\alpha)} \end{aligned} m∗(α)⋅(Jσ)˙⋅s∗(α)=m∗(α)⋅[(Jσ)∇+Ω∗⋅σ−σ⋅Ω∗]⋅s∗(α)=m∗(α)⋅[σ∇∗+σ(I:D∗)−Ω∗⋅σ+σ⋅Ω∗]⋅s∗(α)
忽略体积变化 J = det F ≈ 1 J=\det{F}\approx 1 J=detF≈1
m ˙ ∗ ( α ) ⋅ σ ⋅ s ∗ ( α ) = m ( α ) ⋅ F ˙ ∗ − 1 ⋅ σ ⋅ s ∗ ( α ) = m ∗ ( α ) ⋅ F ∗ ⋅ F ˙ ∗ − 1 ⋅ σ ⋅ s ∗ ( α ) = m ∗ ( α ) ⋅ − L ∗ ⋅ σ ⋅ s ∗ ( α ) \begin{aligned} \dot m^{*(\alpha)}\cdot \sigma\cdot s^{*(\alpha)}&=m^{(\alpha)}\cdot \dot{F}^{*-1}\cdot \sigma\cdot s^{*(\alpha)}\\&=m^{*(\alpha)}\cdot{F^*}\cdot \dot{F}^{*-1}\cdot \sigma\cdot s^{*(\alpha)} \\&=m^{*(\alpha)}\cdot -L^* \cdot \sigma\cdot s^{*(\alpha)} \end{aligned} m˙∗(α)⋅σ⋅s∗(α)=m(α)⋅F˙∗−1⋅σ⋅s∗(α)=m∗(α)⋅F∗⋅F˙∗−1⋅σ⋅s∗(α)=m∗(α)⋅−L∗⋅σ⋅s∗(α)
注: I ˙ = ( F ∗ ⋅ F ∗ − 1 ) ˙ = F ∗ ˙ ⋅ F ∗ − 1 + F ∗ ⋅ F ˙ ∗ − 1 = 0 \dot\bm{I}=\dot\bm{(F^*\cdot F^{*-1})}=\dot\bm{F^*}\cdot \bm{F^{*-1}}+\bm{F^*}\cdot \bm{\dot F^{*-1}}=\bm 0 I˙=(F∗⋅F∗−1)˙=F∗˙⋅F∗−1+F∗⋅F˙∗−1=0
其中: F ∗ ˙ ⋅ F ∗ − 1 = L ∗ \dot\bm{F^*}\cdot \bm{F^{*-1}}=\bm{L^*} F∗˙⋅F∗−1=L∗ ,因此 F ∗ ⋅ F ˙ ∗ − 1 = − L ∗ \bm{F^*}\cdot \bm{\dot F^{*-1}}=\bm{-L^*} F∗⋅F˙∗−1=−L∗
同理:
m ∗ ( α ) ⋅ σ ⋅ s ˙ ∗ ( α ) = m ( ∗ α ) ⋅ σ ⋅ F ∗ ˙ ⋅ s ( α ) = m ∗ ( α ) ⋅ σ ⋅ F ∗ ˙ ⋅ F ∗ − 1 s ∗ ( α ) = m ∗ ( α ) ⋅ σ ⋅ L ∗ ⋅ s ∗ ( α ) \begin{aligned} m^{*(\alpha)}\cdot \sigma\cdot \dot s^{*(\alpha)}&=m^{(*\alpha)}\cdot \sigma\cdot\dot{F^*}\cdot s^{(\alpha)}\\&=m^{*(\alpha)}\cdot \sigma\cdot\dot{F^*}\cdot F^{*-1} s^{*(\alpha)} \\&=m^{*(\alpha)}\cdot \sigma\cdot L ^*\cdot s^{*(\alpha)} \end{aligned} m∗(α)⋅σ⋅s˙∗(α)=m(∗α)⋅σ⋅F∗˙⋅s(α)=m∗(α)⋅σ⋅F∗˙⋅F∗−1s∗(α)=m∗(α)⋅σ⋅L∗⋅s∗(α)
因此:
τ ˙ ( α ) = m ˙ ∗ ( α ) ⋅ [ σ ∇ ∗ + σ ( I : D ∗ ) + Ω ∗ ⋅ σ − σ ⋅ Ω ∗ − L ∗ ⋅ σ + σ ⋅ L ∗ ] ⋅ s ∗ ( α ) = m ˙ ∗ ( α ) ⋅ [ σ ∇ ∗ + σ ( I : D ∗ ) − D ∗ ⋅ σ + σ ⋅ D ∗ ] ⋅ s ∗ ( α ) \begin{aligned} \dot\tau^{(\alpha)}&=\dot m^{*(\alpha)}\cdot [\overset{\nabla}{\bm{\sigma}}^*+\bm{\sigma}\left( \bm{I:D^*}\right)+\Omega^*\cdot \sigma- \sigma\cdot\Omega^*-L ^{*}\cdot \sigma+\sigma\cdot L ^*]\cdot s^{*(\alpha)}\\ &=\dot m^{*(\alpha)}\cdot [\overset{\nabla}{\bm{\sigma}}^*+\bm{\sigma}\left( \bm{I:D^*}\right)-D^{*}\cdot \sigma+\sigma\cdot D^*]\cdot s^{*(\alpha)} \end{aligned} τ˙(α)=
1万+



被折叠的 条评论
为什么被折叠?



