（Leetcode）11. Container With Most Water

题目：

Given n non-negative integers a1, a2, …, an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.

题意：

找到条纵线然后这两条线以及X轴构成的容器能容纳最多的水。

思路：
面积，它受长和高的影响，当长度减小时候，高必须增长才有可能提升面积，所以我们从长度最长时开始递减，然后寻找更高的线来更新候补；

public int maxArea(int[] height) {
        int left = 0;
        int right = height.length-1;
        int area = 0 ;

        while(left<right){
            area = Math.max(area, Math.min(height[left], height[right])*(right-left));

            if(height[left]<height[right]){
                left ++;
            }
            else{
                right --;
            }
        }

        return area;

    }