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HDU 6034 Balala Power!(大数进制)
Balala Power!Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 1317 Accepted Submission(s): 229Problem DescriptionTalente原创 2017-07-25 21:28:39 · 1155 阅读 · 1 评论 -
POJ 2602 Superlong sums
Superlong sumsTime Limit: 2000MS Memory Limit: 65536KTotal Submissions: 23223 Accepted: 6889DescriptionThe creators of a new programming language D++ have found o原创 2017-04-20 17:46:12 · 463 阅读 · 0 评论 -
POJ 1001 Exponentiation(大树乘法)
ExponentiationTime Limit: 500MS Memory Limit: 10000KTotal Submissions: 171270 Accepted: 41478DescriptionProblems involving the computation of exact values of ve原创 2017-08-25 22:34:25 · 561 阅读 · 0 评论 -
HDU 5718 Oracle(大数)
OracleTime Limit: 8000/4000 MS (Java/Others) Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 1235 Accepted Submission(s): 535Problem DescriptionThere is once a ki原创 2017-11-09 21:03:40 · 339 阅读 · 0 评论 -
2017 CCPC 秦皇岛 & ZOJ 3987 - Numbers (贪心+大数)
NumbersTime Limit: 2 Seconds Memory Limit: 65536 KBDreamGrid has a nonnegative integer . He would like to divide into nonnegative integers and minimizes their bitwise or (i.e. an原创 2017-12-19 23:26:44 · 492 阅读 · 0 评论 -
ACM-ICPC 2017 Asia HongKong - A (JAVA大数)
Consider the error function F(x,y,z,n)=∣xn+yn−zn∣F(x,y,z,n)=∣xn+yn−zn∣, where ∣v∣∣v∣ means the absolute value of vv. Given two positive integers nn and zz, our problem is to find two positive integers...原创 2018-03-11 09:07:53 · 1301 阅读 · 6 评论 -
洛谷 - P1492 猩猩散步
点击打开链接 POINT: 答案为C(n+m,m)或者C(n+m,n)。然后因为完全模拟为超时。JAVA大数乘法超时。那么先把分母分子全部质因数分解。把答案化为质因数的个数。然后作高精度低乘 #include <iostream>#include <stdio.h>#include <algorithm>#i...原创 2018-07-10 19:50:25 · 347 阅读 · 0 评论