'.' Matches any single character.
'*' Matches zero or more of the preceding element.
The matching should cover the entire input string (not partial).
The function prototype should be:
bool isMatch(const char *s, const char *p)
Some examples:
isMatch("aa","a") → false
isMatch("aa","aa") → true
isMatch("aaa","aa") → false
isMatch("aa", "a*") → true
isMatch("aa", ".*") → true
isMatch("ab", ".*") → true
isMatch("aab", "c*a*b") → true
这道正则表达式匹配,我分别按照不同的条件来设置if语句,在提交的时候,因为.*匹配问题没有通过,现在先将代码放上,以后再修改
bool isMatch(char* s,char* p){
int i=0,j=0;
if(p[i]!='.'&&p[i]!=s[j]){
return false;
}
i++;
j++;
while(s[j]!='\0'&&p[i]!='\0'){
if(p[i]=='.'||p[i]==s[j]){
i++;
j++;
}else if(p[i]=='*'){
if(p[i-1]=='.'){
return true;
}else if(p[i-1]=='*'){
//
}else{
if(s[j]==p[i]){
j++;
while(s[j]==s[j-1]){
j++;
}
}
i++;
}
}else{
return false;
}
}
if(s[j]=='\0'){
return true;
}else{
return false;
}
}