Problem
Given the root of a binary tree, return the sum of all left leaves.
A leaf is a node with no children. A left leaf is a leaf that is the left child of another node.
Algorithm
Recursion. Use a flag mark it when goes to left sub-tree. When it comes from a left sub-tree and get to the leaf state, we sum the value.
Code
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def sumOfLeftLeaves(self, root: Optional[TreeNode]) -> int:
def dfs(root, s):
if not root.left and not root.right:
if s == 1:
return root.val
else:
return 0
ans = 0
if root.left:
ans += dfs(root.left, 1)
if root.right:
ans += dfs(root.right, 0)
return ans
return dfs(root, 0)