代码随想录算法训练营第十八天|● 513.找树左下角的值● 112. 路径总和 113.路径总和ii

  •  513.找树左下角的值

  • class Solution {
    public:
        int ret = -1;
        int ans=1;
        void dg(TreeNode* node, int step) {
            if (node->left != NULL) {
                if (node->left->right == NULL && node->left->left == NULL) {
                    if (step > ret) {
                        ret = step;
                        ans = node->left->val;
                    }
                }
                if (node->right != NULL) {
                    
                    if (node->right->right == NULL && node->right->left == NULL) {
    
                        if (step > ret) {
                            ret = step;
                            ans = node->right->val;
                        }
                    }
                }
    
                if (node->left) {
                    step++;
                    dg(node->left, step);
                    step--;
                }
                if (node->right) {
                    step++;
                    dg(node->right, step++);
                    step--;
                }
            }
            return;
        }
        int findBottomLeftValue(TreeNode* root) {
            dg(root, 0);
            if (root->left == NULL && root->right == NULL)
                return root->val;
            if()
            return ans;
        }
    };

  •  112. 路径总和  

  • class Solution {
    public:
        int flag;
        int target;
        bool dfs(TreeNode* node, int count) {
            if (!node->left && !node->right) {
                if (count == target)
                    return 1;
                return 0;
            }
            if (node->left) {
                if (dfs(node->left, count + node->left->val))
                    return 1;
            }
            if (node->right) {
    
                if (dfs(node->right, count + node->right->val))
                    return 1;
            }
            return 0;
        }
    
        bool hasPathSum(TreeNode* root, int targetSum) {
            if (root == NULL)
                return 0;
            target = targetSum;
            return dfs(root, root->val);   
        }
    };

  • 113.路径总和ii

  • class Solution {
    public:
        vector<vector<int>> ret;
        vector<int> ans;
        int target;
        void dfs(TreeNode* node, int count) {
            if (!node->left && !node->right) {
                if (count == target) {
                    ret.push_back(ans);
                }
                return;
            }
            if (node->left) {
                ans.push_back(node->left->val);
                dfs(node->left, count + node->left->val);
                ans.pop_back();
            }
            if (node->right) {
                ans.push_back(node->right->val);
                dfs(node->right, count + node->right->val);
                ans.pop_back();
            }
            return;
        }
        vector<vector<int>> pathSum(TreeNode* root, int targetSum) {
            if (root == NULL)
                return {};
            target = targetSum;
            ans.push_back(root->val);
            dfs(root, root->val);
            return ret;
        }
    };

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