方法类似Construct Binary Tree from Postorder and Inorder Traversal http://blog.youkuaiyun.com/menyangyang/article/details/38686975
代码
class Solution
{
public:
TreeNode *buildTree(vector<int> &preorder, vector<int> &inorder)
{
TreeNode *head = NULL;
int inSize = inorder.size();
int preSize = preorder.size();
if(inSize!=preSize||inSize==0)
return head;
return buildTreeHelper(inorder, 0, inSize-1, preorder, 0, preSize-1);
}
TreeNode * buildTreeHelper(vector<int> &inorder,int start0, int end0 ,vector<int> &preorder,int start1, int end1)
{
if(start0>end0||start1>end1)
return NULL;
TreeNode *node = new TreeNode(preorder[start1]);
int leftNum = 0;
int mid;
for(int i = start0; i <= end0; ++i)
{
if(inorder[i]==node->val)
{
mid = i;
break;
}
}
leftNum = mid - start0;
node->left = buildTreeHelper(inorder,start0, mid-1 ,preorder, start1+1, start1+leftNum);
node->right = buildTreeHelper(inorder,mid+1, end0, preorder, start1+leftNum+1, end1);
return node;
}
};
本文详细介绍了如何使用后序和中序遍历的序列来构建二叉树,通过递归的方法解析序列并创建树结构。
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