题目:
Given an array nums, write a function to move all 0's
to the end of it while maintaining the relative order of the non-zero elements.
For example, given nums = [0, 1, 0, 3, 12], after calling your function, nums should
be [1, 3, 12, 0, 0].
Note:
- You must do this in-place without making a copy of the array.
- Minimize the total number of operations.
思路:
好简洁的代码呀!注意理解k的含义。
代码:
class Solution {
public:
void moveZeroes(vector<int>& nums) {
for(int i = 0, k = 0; i < nums.size(); ++i) {
if(nums[i] != 0) {
swap(nums[i], nums[k++]);
}
}
}
};
本文介绍了一种简洁高效的算法,用于将数组中所有零元素移至末尾,同时保持非零元素的相对顺序不变。该算法通过一次遍历实现,无需额外空间,并尽量减少操作次数。
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