py进行排序

#读取数据
with open('./job.407755.err') as f:
    lines = f.readlines()
#筛选带有set的字符
new_lines=[]
for line in lines:
    if "Set" in line:
        new_lines.append(line)
        
#从大到小排序
sorted(new_lines, 
       key=lambda x: int(x.strip().split('=')[-1]),
       reverse=True
      )