约瑟夫问题

P1996 约瑟夫问题 - 洛谷 | 计算机科学教育新生态 (luogu.com.cn)

 循环链表

int ne[1000005];
inline void solve()
{
    int n, m;
    cin >> n >> m;
    for (int i = 0; i < n; i++)
        ne[i] = i + 1;
    ne[n] = 1;
    int p = 0;
    for (int i = 1; i <= n; i++)
    {
        for (int j = 1; j < m; j++)
            p = ne[p];
        cout << p[ne] << " ";
        ne[p] = ne[ne[p]];
    }
}

队列

queue<int> a;
inline void solve()
{
    int n, m;
    cin >> n >> m;
    ff(i,n)
        a.push(i);
    int k = 1;
    while(!a.empty()){
        if(k==m){
            cout << a.front() << " ";
            a.pop();
            k = 1;
        }
        else {
            k++;
            a.push(a.front()); // 把head压进队尾
            a.pop();
        }
    }
}