方法一:(byte) (0xff & Integer.parseInt(strings[i], 16));// 获得当前16进制字符串对应的 byte数值
添加到byte数组,然后 以指定编码 转换:new String(hanzi, "utf-8")。
String string = "53+ff+55+23+04+00+21+"
+ "e7+88+b1+e5+a4+"
+ "9a+e6+b7+b1+e7+"
+ "97+9b+e5+a4+9a+"
+ "e4+b9+85+2d+e4+"
+ "b8+9c+e6+9d+a5+"
+ "e4+b8+9c+e5+be+"
+ "80+00+"
+ "e1";
String[] strings = string.split("\\+");
int length = Integer.parseInt(strings[3], 16);
StringBuffer buffer = new StringBuffer();
byte hanzi[] = new byte[length - 3];
for (int i = 7; i < length - 3 + 7; i++) {
hanzi[i - 7] = (byte) (0xff & Integer.parseInt(strings[i], 16));// 获得当前16进制字符串对应的
// byte数值
}
try {
// 以utf-8 编码 byte数组
System.out.println(new String(hanzi, "utf-8"));
} catch (UnsupportedEncodingException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
方法二:
更具通用性
private static String hexString = "0123456789ABCDEF";
public static String decode(String bytes) {
ByteArrayOutputStream baos = new ByteArrayOutputStream(bytes.length() / 2);
// 将每2位16进制整数组装成一个字节
for (int i = 0; i < bytes.length(); i += 2)
//获得当前16进制字符串(如 e7) 的byte 值
baos.write((hexString.indexOf(bytes.charAt(i)) << 4 | hexString.indexOf(bytes.charAt(i + 1))));
return new String(baos.toByteArray());
}