题目:
Write a program to check whether a given number is an ugly number.
Ugly numbers are positive numbers whose prime factors only include 2, 3, 5. For example, 6,
8 are ugly while 14 is not ugly since it includes another prime factor 7.
Note that 1 is typically treated as an ugly number.
解答:
如题,如果一个数是ugly number,那么它一定可以表示成为2^x * 3^y * 5^z的形式
也就是说这个数字在不断除以2,3,5的情况下,最终一定会得到1,注意数字为非正数的时候直接返回false
class Solution {
public:
bool isUgly(int num) {
if(num <= 0)
return false;
while(true)
{
if(num % 2 == 0)
num = num / 2;
else if(num %3 == 0)
num = num / 3;
else if(num % 5 == 0)
num = num / 5;
else
break;
}
if(num == 1)
return true;
return false;
}
};
本文介绍了一种使用C++编程语言判断一个给定数字是否为丑数的方法。丑数定义为仅包含质因数2、3和5的正整数。文章提供了一个具体的程序实现案例,并解释了其工作原理。
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