题目源自于Leetcode。
简单的递归题。
题目:Given two binary trees, write a function to check if they are equal or not.
Two binary trees are considered equal if they are structurally identical and the nodes have the same value.
思路:关键在于递归的结束条件和应该返回的真假值。
代码:
/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
bool isSameTree(TreeNode *p, TreeNode *q) {
// IMPORTANT: Please reset any member data you declared, as
// the same Solution instance will be reused for each test case.
if(p == NULL && q == NULL)
return true;
else if( (p != NULL && q == NULL) || (p == NULL && q != NULL))
return false;
else
{
if(p->val == q->val)
return isSameTree(p->left, q->left) && isSameTree(p->right, q->right);
else
return false;
}
}
};

本文介绍了一道来自LeetCode的二叉树等价判断问题。通过递归的方法检查两个二叉树是否结构相同且节点值相等。文章提供了完整的C++实现代码,并解释了递归终止条件及返回值。
1268

被折叠的 条评论
为什么被折叠?



