输入一个链表的头节点,从尾到头反过来返回每个节点的值(用数组返回)。
示例 1:
输入:head = [1,3,2]
输出:[2,3,1]
限制:
0 <= 链表长度 <= 10000
方法一:
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
class Solution {
public int[] reversePrint(ListNode head) {
ListNode temp = head;
int length = 0;
while(temp != null){
length++;
temp = temp.next;
}
int[] ls = new int[length];
for(int i=ls.length-1;i>=0;i--){
ls[i] = head.val;
head = head.next;
if(head == null){
break;
}
}
return ls;
}
}
方法二:使用栈:
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
import java.util.*;
class Solution {
public int[] reversePrint(ListNode head) {
Stack<ListNode> stack = new Stack<>();
while(head!=null){
stack.add(head);
head = head.next;
}
int[] ls = new int[stack.size()];
for(int i=0;i<ls.length;i++){
ls[i] = stack.pop().val;
}
return ls;
}
}