[leetcode] Majority Element

Cabinathor

于 2015-06-02 21:39:29 发布

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本文链接：https://blog.youkuaiyun.com/lmxmimihuhu/article/details/46335533

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本文介绍了一个高效的算法来解决LeetCode上的多数元素问题。该问题要求找出数组中出现次数超过一半的元素。通过一个简单的C++实现，我们展示了如何仅遍历一次数组就能找到多数元素，该方法基于Boyer-Moore投票算法。

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From : https://leetcode.com/problems/majority-element/

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times.

You may assume that the array is non-empty and the majority element always exist in the array.

class Solution {
public:
    int majorityElement(vector<int>& nums) {
        int flag = 1, cur = nums[0];
        for(int i=1; i<nums.size(); i++) {
            if(flag == 0) cur = nums[i];
            if(cur == nums[i]) flag++;
            else flag--;
        }
        return cur;
    }
};