[leetcode] Contains Duplicate III

最新推荐文章于 2020-04-25 23:41:16 发布

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本文探讨了如何在数组中找到两个元素，它们之间的差值不超过指定阈值t，并且它们的索引之差不超过k。

From : https://leetcode.com/problems/contains-duplicate-iii/

Given an array of integers, find out whether there are two distinct indices i and j in the array such that the difference between nums[i] andnums[j] is at most t and the difference between i and j is at most k.

class Solution {
public:
    bool containsNearbyAlmostDuplicate(vector<int>& nums, int k, int t) {
        if(k<1 || t<0 || nums.size() < 2) return false;
		multiset<int> box;
		for(int i=0; i<nums.size()-1; ) {
			box.insert(nums[i]);
			i++;
			set<int>::iterator it = box.lower_bound(nums[i]-t);
			if(it!=box.end()) {
			    if(*it-nums[i]>=-t && *it-nums[i]<=t) return true;
			}
			if(i>=k) {
				box.erase(nums[i-k]);
			}
		}
		return false;
    }
};