Description
给出正方形(Square)、长方形(Rectangle)、立方体(Cuboid)的边长,求周长、面积、体积。
Square类只需存一条边长,构造函数产生一条输出,有边长、周长、面积的函数。
Rectangle类需存长和宽,若从Square类派生而来,因此只需增加一条边,构造函数产生一条输出,有长、宽、周长、面积的函数。
Cuboid类需存长宽高,若从Rectangle类派生而来,因此也只增加一条边,构造函数产生一条输出,有长、宽、高、周长、面积、体积的函数。它的周长定义为所有棱长之和。
请仔细阅读append.cc代码,并设计好正方形、长方形、立方体派生关系,使main()函数能够运行并得到正确的输出。
Input
输入分为三部分,每一部分都已一个整数n开始,表示后面有n组测试数据。
在第一部分测试数据中,每组是一个整数,表示正方形的边长。
在第二部分测试数据中,每组是两个整数,表示长方形的长和宽。
在第三部分测试数据中,每组是三个整数, 表示立方体的长和宽。
Output
每组测试数据对应的输出为两部分,前面是构造函数的输出,最后是输出图形的信息,包括长宽高、周长、面积、体积等信息,格式见sample;
Sample Input
1
4
1
3 4
1
3 4 6
Sample Output
Construct Square (4)
A Square length 4, Perimeter 16, Area 16
=========================
Construct Square (3)
Construct Rectangle (3, 4)
A Rectangle length 3, width 4, Perimeter 14, Area 12
=========================
Construct Square (3)
Construct Rectangle (3, 4)
Construct Cuboid (3, 4, 6)
A Cuboid length 3, width 4, height 6, Perimeter 52, Area 108, Volume 72
HINT
Append Code
int main()
{
int cases, l, w, h;
cin >> cases;
for(int i = 1; i <= cases; ++i)
{
cin >> l;
Square squa(l);
cout << "A Square length " << squa.length() << ", ";
cout << "Perimeter " << squa.perimeter() << ", ";
cout << "Area " << squa.area() << endl;
}
cout << "=========================" << endl;
cin >> cases;
for(int i = 1; i <= cases; ++i)
{
cin >> l >> w;
Rectangle rect(l, w);
cout << "A Rectangle length " << rect.length() << ", width " << rect.width() << ", ";
cout << "Perimeter " << rect.perimeter() << ", ";
cout << "Area " << rect.area() << endl;
}
cout << "=========================" << endl;
cin >> cases;
for(int i = 1; i <= cases; ++i)
{
cin >> l >> w >> h;
Cuboid cubo(l, w, h);
cout << "A Cuboid length " << cubo.length() << ", width " << cubo.width() << ", height " << cubo.height() << ", ";
cout << "Perimeter " << cubo.perimeter() << ", ";
cout << "Area " << cubo.area() << ", ";
cout << "Volume " << cubo.volume() << endl;
}
}
Accepted Code
#include <iostream>
using namespace std;
class Square {
protected:
int len;
public:
Square(int l = 0): len(l) {
cout << "Construct Square (" << len << ")\n";
}
int length() { return len; }
int perimeter() { return 4*len; }
int area() { return len*len; }
};
class Rectangle : public Square {
protected:
int wid;
public:
Rectangle(int l = 0, int w = 0) : Square(l), wid(w) {
cout << "Construct Rectangle (" << len << ", " << wid << ")\n";
}
int width() { return wid; }
int perimeter() { return 2*len + 2*wid; }
int area() { return len*wid; }
};
class Cuboid : public Rectangle {
protected:
int hei;
public:
Cuboid(int l = 0, int w = 0, int h = 0) : Rectangle(l, w), hei(h) {
cout << "Construct Cuboid (" << len << ", " << wid << ", " << hei << ")\n";
}
int height() { return hei; }
int perimeter() { return 4 * len + 4 * hei + 4 * wid;}
int area() { return 2*len*wid + 2*len*hei + 2*wid*hei;}
int volume() { return len*hei*wid; }
};
int main()
{
int cases, l, w, h;
cin >> cases;
for(int i = 1; i <= cases; ++i)
{
cin >> l;
Square squa(l);
cout << "A Square length " << squa.length() << ", ";
cout << "Perimeter " << squa.perimeter() << ", ";
cout << "Area " << squa.area() << endl;
}
cout << "=========================" << endl;
cin >> cases;
for(int i = 1; i <= cases; ++i)
{
cin >> l >> w;
Rectangle rect(l, w);
cout << "A Rectangle length " << rect.length() << ", width " << rect.width() << ", ";
cout << "Perimeter " << rect.perimeter() << ", ";
cout << "Area " << rect.area() << endl;
}
cout << "=========================" << endl;
cin >> cases;
for(int i = 1; i <= cases; ++i)
{
cin >> l >> w >> h;
Cuboid cubo(l, w, h);
cout << "A Cuboid length " << cubo.length() << ", width " << cubo.width() << ", height " << cubo.height() << ", ";
cout << "Perimeter " << cubo.perimeter() << ", ";
cout << "Area " << cubo.area() << ", ";
cout << "Volume " << cubo.volume() << endl;
}
}
本文探讨了在C++中通过继承实现正方形、长方形和立方体类的设计方法,展示了如何利用基类和派生类来计算这些形状的周长、面积和体积。文章详细解释了每个类的构造函数、成员函数以及它们之间的派生关系。
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