【Leetcode-Hard-124】Binary Tree Maximum Path Sum

【Leetcode-Hard-124】Binary Tree Maximum Path Sum

题目

Given a binary tree, find the maximum path sum.

For this problem, a path is defined as any sequence of nodes from some starting node to any node in the tree along the parent-child connections. The path must contain at least one node and does not need to go through the root.

For example:
Given the below binary tree,

       1
      / \
     2   3
 

Return 6.

思路

递归

二叉树的最大路径和。
路径,如果选择当前结点,而且其父结点被选择,则它的左右孩子结点最多只能选择一个。

程序

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */


/**
 *       -1
 *      /  |
 *     2  3  
 *        / | 
 *       -1  2
 *       /
 *      4  
 */
class Solution {

    int max = Integer.MIN_VALUE;

    public int maxPathSum(TreeNode root){
        helper(root);
        return max;
    }

    public int helper(TreeNode root) {
        if (root == null) return 0;
        int left = Math.max(0, helper(root.left));
        int right = Math.max(0, helper(root.right));
        max = Math.max(max, left + right + root.val);
        return Math.max(left, right) + root.val;

    }
}
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