LeetCode 412. Fizz Buzz

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本文介绍了一个经典的编程面试题——FizzBuzz问题，并提供了一种使用C++语言的解决方案。该问题要求从1到n输出数字，但对3的倍数输出Fizz，对5的倍数输出Buzz，对既是3又是5的倍数则输出FizzBuzz。

412. Fizz Buzz
Write a program that outputs the string representation of numbers from 1 to n.

But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and five output “FizzBuzz”.

Example:

n = 15,

Return:
[
"1",
"2",
"Fizz",
"4",
"Buzz",
"Fizz",
"7",
"8",
"Fizz",
"Buzz",
"11",
"Fizz",
"13",
"14",
"FizzBuzz"
]

分析：几个if else 语句分别对是否能被15整除、5整除、3整除进行赋值～

class Solution {
public:
    vector<string> fizzBuzz(int n) {
        vector<string> result(n);
        for(int i = 0; i < n; i++) {
            if((i + 1) % 15 == 0)
                result[i] = "FizzBuzz";
            else if((i + 1) % 5 == 0)
                result[i] = "Buzz";
            else if((i + 1) % 3 == 0)
                result[i] = "Fizz";
            else
                result[i] = to_string(i + 1);
        }
        return result;
    }
};