面试题35:复杂链表的复制
题目描述:
输入一个复杂链表(每个节点中有节点值,以及两个指针,一个指向下一个节点,另一个特殊指针指向任意一个节点),返回结果为复制后复杂链表的head。(注意,输出结果中请不要返回参数中的节点引用,否则判题程序会直接返回空)
代码:
/*
struct RandomListNode {
int label;
struct RandomListNode *next, *random;
RandomListNode(int x) :
label(x), next(NULL), random(NULL) {
}
};
*/
class Solution {
public:
void CloneNode(RandomListNode* pHead){
RandomListNode* pNode=pHead;
while(pNode){
RandomListNode* pCloned=new RandomListNode(pNode->label);
pCloned->next=pNode->next;
pCloned->random=nullptr;
pNode->next=pCloned;
pNode=pCloned->next;
}
}
void CloneRandom(RandomListNode* pHead){
RandomListNode* pNode=pHead;
while(pNode){
RandomListNode* pCloned=pNode->next;
if(pNode->random){
pCloned->random=pNode->random->next;
}
pNode=pCloned->next;
}
}
RandomListNode* ReconstructNode(RandomListNode* pHead){
RandomListNode* pNode=pHead;
RandomListNode* pClonedHead=nullptr;
RandomListNode* pCloned=nullptr;
if(pNode){
pClonedHead=pCloned=pNode->next;
pNode->next=pCloned->next;
pNode=pNode->next;
}
while(pNode){
pCloned->next=pNode->next;
pCloned=pCloned->next;
pNode->next=pCloned->next;
pNode=pNode->next;
}
return pClonedHead;
}
RandomListNode* Clone(RandomListNode* pHead)
{
CloneNode(pHead);
CloneRandom(pHead);
return ReconstructNode(pHead);
}
};