Given an array S of n integers, are there elements a, b, c in S such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero.
Note: The solution set must not contain duplicate triplets.
For example, given array S = [-1, 0, 1, 2, -1, -4], A solution set is: [ [-1, 0, 1], [-1, -1, 2] ]
这道题很重要的一点就是要去重。
class Solution {
public List<List<Integer>> threeSum(int[] nums) {
List<List<Integer>> res = new ArrayList<>();
if(nums == null || nums.length < 3) return res;
Arrays.sort(nums);
for(int i = 0; i < nums.length - 2; i++){
// 去重
if(i != 0 && nums[i] == nums[i - 1]) continue;
int left = i + 1;
int right = nums.length - 1;
while(left < right){
int sum = nums[i] + nums[left] + nums[right];
if(sum == 0){
res.add(Arrays.asList(nums[i], nums[left], nums[right]));
// 去重
while(left + 1 < right && nums[left + 1] == nums[left]) left++;
while(right - 1 > left && nums[right - 1] == nums[right]) right--;
left++;
right--;
} else if (sum > 0){
right--;
} else {
left++;
}
}
}
return res;
}
}