Given a linked list, determine if it has a cycle in it.
Follow up:
Can you solve it without using extra space?
public class Solution {
public boolean hasCycle(ListNode head) {
if(head == null || head.next == null)
return false;
ListNode slow = head;
ListNode fast = head;
while(true){
slow = slow.next;
fast = fast.next.next;
if(fast == null || fast.next == null)
return false;
if(fast == slow)
return true;
}
}
}

本文介绍了一种使用快慢指针解决链表循环问题的算法,包括原题解析、优化思路和代码实现,适用于链表操作的学习和实际应用。
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