output
standard output
You are given two segments [l1;r1][l1;r1] and [l2;r2][l2;r2] on the xx-axis. It is guaranteed that l1<r1l1<r1 and l2<r2l2<r2. Segments may intersect, overlap or even coincide with each other.
The example of two segments on the xx-axis.
Your problem is to find two integers aa and bb such that l1≤a≤r1l1≤a≤r1, l2≤b≤r2l2≤b≤r2 and a≠ba≠b. In other words, you have to choose two distinct integer points in such a way that the first point belongs to the segment [l1;r1][l1;r1] and the second one belongs to the segment [l2;r2][l2;r2].
It is guaranteed that the answer exists. If there are multiple answers, you can print any of them.
You have to answer qq independent queries.
Input
The first line of the input contains one integer qq (1≤q≤5001≤q≤500) — the number of queries.
Each of the next qq lines contains four integers l1i,r1i,l2il1i,r1i,l2i and r2ir2i (1≤l1i,r1i,l2i,r2i≤109,l1i<r1i,l2i<r2i1≤l1i,r1i,l2i,r2i≤109,l1i<r1i,l2i<r2i) — the ends of the segments in the ii-th query.
Output
Print 2q2q integers. For the ii-th query print two integers aiai and bibi — such numbers that l1i≤ai≤r1il1i≤ai≤r1i, l2i≤bi≤r2il2i≤bi≤r2i and ai≠biai≠bi. Queries are numbered in order of the input.
It is guaranteed that the answer exists. If there are multiple answers, you can print any.
Example
input
Copy
5 1 2 1 2 2 6 3 4 2 4 1 3 1 2 1 3 1 4 5 8
output
Copy
2 1 3 4 3 2 1 2 3 7
代码:
#include<cstdio>
#include<cstring>
#include<iostream>
#include<algorithm>
using namespace std;
int main()
{
int n;
cin>>n;
int l1,r1,l2,r2;
for(int t=0;t<n;t++)
{
scanf("%d%d%d%d",&l1,&r1,&l2,&r2);
int fi=l1;
int se;
for(int t=l2;t<=r2;t++)
{
if(t!=fi)
{
se=t;
break;
}
}
cout<<fi<<" "<<se<<endl;
}
return 0;
}
本文探讨了一个算法问题,即在给定的两个区间内找到两个不同的整数点,每个点属于其中一个区间。通过遍历和比较,算法确保了所选点的唯一性和有效性,适用于多个查询。
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