HDU-Digital Roots(思维+大数字符串模拟)

最新推荐文章于 2020-07-04 17:53:28 发布

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本文介绍了一种计算数字根的方法，通过不断累加整数的各位数字直至得到单个数字，即数字根。文章提供了处理大数的字符串模拟输入代码实现，包括循环求解过程，展示了如何处理如24和39等正整数的数字根计算。

The digital root of a positive integer is found by summing the digits of the integer. If the resulting value is a single digit then that digit is the digital root. If the resulting value contains two or more digits, those digits are summed and the process is repeated. This is continued as long as necessary to obtain a single digit.

For example, consider the positive integer 24. Adding the 2 and the 4 yields a value of 6. Since 6 is a single digit, 6 is the digital root of 24. Now consider the positive integer 39. Adding the 3 and the 9 yields 12. Since 12 is not a single digit, the process must be repeated. Adding the 1 and the 2 yeilds 3, a single digit and also the digital root of 39.

Input

The input file will contain a list of positive integers, one per line. The end of the input will be indicated by an integer value of zero.

Output

For each integer in the input, output its digital root on a separate line of the output.

Sample Input

24
39
0

Sample Output

6
3

思路：循环求解，但要考虑输入的数特别大时，就要考虑字符串模拟大数的输入了

代码：

#include<cstdio>
#include<cstring>
#include<algorithm>
#include<iostream>

using namespace std;
int sum;
string n;
int root(int x) {
	sum=0;
	while(x) {
		sum+=x%10;
		x/=10;
	}
	return sum;
}

int main() {

	while(cin>>n) {
		if(n=="0") {
			break;
		}
		int s=0;
		for(int t=0; t<n.length(); t++) {
			s+=n[t]-'0';
		}

		if(s>=10) {
			while(root(s)>=10) {
				s=sum;
			}
		} else {
			sum=s;
		}
		cout<<sum<<endl;
	}


	return 0;
}