Boost.Thread库中boost::thread() 无启动参数的解决方法

/**

 * Create only by new operator, delete by owner

 * joinable m_thread

 */

class LaThread {

   

private:

    boost::thread* m_thread;

 

    static static_run(LaThread* This) {

       This->run();

    }

 

protected:

    virtual void run() = 0;

 

public:

    LaThread() : m_thread(NULL) {}

    /**

     * Requires: threat ended

     */   

    virtual ~LaThread(){

       if( m_thread != NULL )

           delete m_thread;

    }

 

public:

    void start() {

       if( m_thread != NULL ) {

           throw std::exception(_T("m_thread != NULL"));

       }

       m_thread = new boost::thread( boost::bind(static_run, this) );

    }

 

    void join() {

       if( m_thread == NULL ) {

           throw std::exception(_T("m_thread == NULL"));

       }

       m_thread->join();

    }

};

 

class TestThread : public LaThread {

private:

    int arg;

public:

    TestThread( int arg ) {

       this->arg = arg;

    }

public:

    virtual void run() {

       _RPT3(_CRT_WARN, "[%d]\t[%s]\t[%s]\n", ::GetCurrentThreadId(), _T("Hi I'm new thread!"), __FUNCTION__);             

    }     

};

主要看点是：

new boost::thread( boost::bind(static_run, this) );

boost::bind使可以使 static_run(LaThread* This) 变成满足 boost::thread ( boost::function0 fuc )要求的函数。

C++ ISO 1998 的确并不是一个STL Container那么简单啊。还有boost::mem_fn呢。

解决这类别扭问题的方法的：

google: Boost Thread parameter

回复者（可能是Thread文档的开发者），说这样的说明将会加入到下个版本的文档中。