/**
* Create only by new operator, delete by owner
* joinable m_thread
*/
class LaThread {
private:
boost::thread* m_thread;
static static_run(LaThread* This) {
This->run();
}
protected:
virtual void run() = 0;
public:
LaThread() : m_thread(NULL) {}
/**
* Requires: threat ended
*/
virtual ~LaThread(){
if( m_thread != NULL )
delete m_thread;
}
public:
void start() {
if( m_thread != NULL ) {
throw std::exception(_T("m_thread != NULL"));
}
m_thread = new boost::thread( boost::bind(static_run, this) );
}
void join() {
if( m_thread == NULL ) {
throw std::exception(_T("m_thread == NULL"));
}
m_thread->join();
}
};
class TestThread : public LaThread {
private:
int arg;
public:
TestThread( int arg ) {
this->arg = arg;
}
public:
virtual void run() {
_RPT3(_CRT_WARN, "[%d]/t[%s]/t[%s]/n", ::GetCurrentThreadId(), _T("Hi I'm new thread!"), __FUNCTION__);
}
};
主要看点是:
new boost::thread( boost::bind(static_run, this) );
boost::bind使可以使 static_run(LaThread* This) 变成满足 boost::thread ( boost::function0 fuc )要求的函数。
C++ ISO 1998 的确并不是一个STL Container那么简单啊。还有boost::mem_fn呢。
解决这类别扭问题的方法的:
google: Boost Thread parameter
回复者(可能是Thread文档的开发者),说这样的说明将会加入到下个版本的文档中。