Directory
Basic Concept of the Stack and the Queue
- The
stackis last-in-fist-out(LIFO) - The
queueis first in first out(FIFO) - They don’t allow traversal, and don’t provide the iterator.
- The
stackuse pluggable containers to implement its function and provide unified interfaces to the outside world. That is, we can control what container to implement the part of the stack.
LeetCode 232. Implement Queue using Stacks
Solution:
class MyQueue {
Stack<Integer> stackIn;
Stack<Integer> stackOut;
// Initiallize the data structure
public MyQueue() {
stackIn = new Stack<>();
stackOut = new Stack<>();
}
public void push(int x) {
stackIn.push(x);
}
public int pop() {
dumpStackIn();
return stackOut.pop();
}
public int peek() {
dumpStackIn();
return stackOut.peek();
}
public boolean empty() {
return stackIn.isEmpty()&&stackOut.isEmpty();
}
//If the stackOut is empty, dump all of the elements of the stackIn into the stackOut
private void dumpStackIn(){
if(!stackOut.isEmpty())
return;
while(!stackIn.isEmpty()){
stackOut.push(stackIn.pop());
}
}
}
/**
* Your MyQueue object will be instantiated and called as such:
* MyQueue obj = new MyQueue();
* obj.push(x);
* int param_2 = obj.pop();
* int param_3 = obj.peek();
* boolean param_4 = obj.empty();
*/
Thought:
- When popping the stack:
- If the
stackOutis empty, dump all of the elements of thestackIninto thestackOut. Then do pop() from thestackOut - If the
stackOutis not empty, do pop() directly from thestackOut
- If the
LeetCode 225. Implement Stack using Queues
Solution:
1、Use two queues for implementation
class MyStack {
Queue<Integer> queue1;
Queue<Integer> queue2; // auxiliary queue for backup
public MyStack() {
queue1 = new LinkedList<>();
queue2 = new LinkedList<>();
}
public void push(int x) {
// put x in to auxiliary queue first
queue2.offer(x);
// then dump all elements of the queue1 in to the queue2
while(!queue1.isEmpty())
queue2.offer(queue1.poll());
// dump all elements of the queue2 into queue1
Queue<Integer> queueTemp = new LinkedList<>();
queue1 = queue2;
queue2 = queueTemp;
}
public int pop() {
return queue1.poll();
}
public int top() {
return queue1.peek();
}
public boolean empty() {
return queue1.isEmpty();
}
}
/**
* Your MyStack object will be instantiated and called as such:
* MyStack obj = new MyStack();
* obj.push(x);
* int param_2 = obj.pop();
* int param_3 = obj.top();
* boolean param_4 = obj.empty();
*/
Thought:
- Put
xin to auxiliaryqueue2first - Dump all elements of the
queue1in to thequeue2 - Dump all elements of the queue2 into queue1
2、Use one queue for implementation
class MyStack {
Queue<Integer> queue;
public MyStack() {
queue = new LinkedList<>();
}
// When push a `x`, reorder the queue. Put the `x` at the front of the queue
public void push(int x) {
queue.offer(x);
int size = queue.size();
// move all of the elements except `x`
while(size-- > 1)
queue.offer(queue.poll());
}
public int pop() {
return queue.poll();
}
public int top() {
return queue.peek();
}
public boolean empty() {
return queue.isEmpty();
}
}
/**
* Your MyStack object will be instantiated and called as such:
* MyStack obj = new MyStack();
* obj.push(x);
* int param_2 = obj.pop();
* int param_3 = obj.top();
* boolean param_4 = obj.empty();
*/
Thought:
- When push a
x, reorder the queue. Put thexat the front of the queue - In the
while loop, move all of the elements exceptx
这篇博客介绍了如何利用栈和队列的基本概念来实现LeetCode上的232题(用栈实现队列)和225题(用队列实现栈)。在232题中,通过两个栈来模拟队列的push、pop、peek和empty操作;而在225题中,博主提供了两种方法实现用队列实现栈,一种是使用两个队列,另一种是仅使用一个队列并重新排序。文章详细阐述了每种方法的思路和实现过程。
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