HDU-5832 HDU-1212/2016网络选拔赛/大数取余

A water problem Time Limit: 5000/2500 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 326    Accepted Submission(s): 180 Problem Description Two planets named Haha and Xixi in the universe and they were created with the universe beginning. There is 73 days in Xixi a year and 137 days in Haha a year. Now you know the days N after Big Bang, you need to answer whether it is the first day in a year about the two planets.   Input There are several test cases(about 5 huge test cases). For each test, we have a line with an only integer N(0≤N) , the length of N is up to 10000000 .   Output For the i-th test case, output Case #i: , then output "YES" or "NO" for the answer.   Sample Input 10001 0 333   Sample Output Case #1: YES Case #2: YES Case #3: NO   Author UESTC   Source 2016中国大学生程序设计竞赛 - 网络选拔赛

Cmod(A*B)==0  =CmodA==0&&CmodB==0

 

   C

---------- =integer

  A*B

#include <iostream>
using namespace std;
#define N 12000000
#define INF 1<<30
char s[N];
int main()
{
    int k=0,len,x,d,i;
    while(scanf("%s", s) != EOF)
    {
        k++;
        len = strlen(s);
        x=10001;
        d=0;
        for(i=0;i<len;i++)
            d=(d*10+(s[i]-'0')%x)%x;

        if(d==0)
            printf("Case #%d: YES\n",k);
        else
            printf("Case #%d: NO\n",k);
    }
    return 0;
}

Big Number

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 7409    Accepted Submission(s): 5124

Problem Description

As we know, Big Number is always troublesome. But it's really important in our ACM. And today, your task is to write a program to calculate A mod B.

To make the problem easier, I promise that B will be smaller than 100000.

Is it too hard? No, I work it out in 10 minutes, and my program contains less than 25 lines.

 

Input

The input contains several test cases. Each test case consists of two positive integers A and B. The length of A will not exceed 1000, and B will be smaller than 100000. Process to the end of file.

 

Output

For each test case, you have to ouput the result of A mod B.

 

Sample Input

   

    2 3
12 7
152455856554521 3250
   

 

Sample Output

   

    2
5
1521
   

 

Author

Ignatius.L

 

Source

杭电ACM省赛集训队选拔赛之热身赛

#include <iostream>

#include<string.h>

using namespace std ;

#define N 1005

char s [N ];

int main()

{

  int k = 0 ,len ,x ,d ,i ;

   while(scanf ( "%s" ,s )!= EOF ) {
        cin >>x ;
        k ++;
        len = strlen (s );
        d = 0 ;

      for(i = 0 ;i <len ;i ++)
            d =(d * 10 +(s [i ]- '0' )%x )%x ;
        printf ( "%d\n" ,d );

   }

  return 0 ;

}