You are climbing a stair case. It takes n steps to reach to the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
用动态规划做,然后发现其实就是斐波那契数列。
代码:
class Solution {
public:
int climbStairs(int n) {
if(n==0) return 0;
if(n==1) return 1;
vector<int>res(n+1);
res[1]=1;res[2]=2;
for(int i=3;i<=n;i++)
{
res[i]=res[i-1]+res[i-2];
}
return res[n];
}
};