hdu 1002 A + B Problem II(Java)

最新推荐文章于 2021-02-23 08:14:36 发布

原创最新推荐文章于 2021-02-23 08:14:36 发布 · 356 阅读

0 ·

CC 4.0 BY-SA版权

文章标签：

#hdu #Java

hdu 专栏收录该内容

4 篇文章

订阅专栏

本文介绍了一个简单的编程问题——处理非常大的整数相加。使用Java实现，通过BigInteger类解决了传统整数类型无法处理的问题。文章提供了一段示例代码，展示了如何输入两个大整数并计算它们的和。

Problem Description

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

Output

For each test case, you should output two lines. The first line is “Case #:”, # means the number of the test case. The second line is the an equation “A + B = Sum”, Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

代码

import java.math.BigInteger;
import java.util.Scanner;

public class Main{

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        int t = 0;
        boolean isFrist = true;
        while(t++<n){
            BigInteger a = sc.nextBigInteger();
            BigInteger b = sc.nextBigInteger();
            BigInteger c = a.add(b);
            if(!isFrist){
                System.out.println();
            }else{
                isFrist=!isFrist;
            }
            System.out.println("Case "+t+":");
            System.out.println(a.toString()+" + "+b.toString()+" = "+c.toString());
        }
    }
}