LeetCode 463. Island Perimeter

本文介绍了一种通过逐个扫描二维网格来计算岛屿周长的方法。该算法适用于LeetCode上的一道题目,即给定一个由0和1组成的矩阵,1表示陆地,0表示水域,求岛屿的周长。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >

原题网址:https://leetcode.com/problems/island-perimeter/

You are given a map in form of a two-dimensional integer grid where 1 represents land and 0 represents water. Grid cells are connected horizontally/vertically (not diagonally). The grid is completely surrounded by water, and there is exactly one island (i.e., one or more connected land cells). The island doesn't have "lakes" (water inside that isn't connected to the water around the island). One cell is a square with side length 1. The grid is rectangular, width and height don't exceed 100. Determine the perimeter of the island.

Example:

[[0,1,0,0],
 [1,1,1,0],
 [0,1,0,0],
 [1,1,0,0]]

Answer: 16
Explanation: The perimeter is the 16 yellow stripes in the image below:

方法:逐个扫描。

public class Solution {
    public int islandPerimeter(int[][] grid) {
        int p = 0;
        for(int i = 0; i < grid.length; i++) {
            for(int j = 0; j < grid[i].length; j++) {
                if (grid[i][j] == 0) continue;
                if (i == 0 || grid[i - 1][j] == 0) p++;
                if (i == grid.length - 1 || grid[i + 1][j] == 0) p++;
                if (j == 0 || grid[i][j - 1] == 0) p++;
                if (j == grid[i].length - 1 || grid[i][j + 1] == 0) p++;
            }
        }
        return p;
    }
}


评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值