LeetCode 293. Flip Game（反转游戏）

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本文介绍了一个简单的游戏算法问题——Flip Game。玩家需将字符串中的连续两个'+'字符翻转为'-'，文章提供了实现这一功能的Java代码示例，并解释了如何通过一次有效移动生成所有可能的状态。

原题网址：https://leetcode.com/problems/flip-game/

You are playing the following Flip Game with your friend: Given a string that contains only these two characters: + and -, you and your friend take turns to flip twoconsecutive "++" into "--". The game ends when a person can no longer make a move and therefore the other person will be the winner.

Write a function to compute all possible states of the string after one valid move.

For example, given s = "++++", after one move, it may become one of the following states:

[
  "--++",
  "+--+",
  "++--"
]

If there is no valid move, return an empty list [].

方法：直接扫描，时间复杂度O(n)

public class Solution {
    public List<String> generatePossibleNextMoves(String s) {
        List<String> results = new ArrayList<>();
        char[] sa = s.toCharArray();
        for(int i=0; i<sa.length-1; i++) {
            if (sa[i]=='+' && sa[i+1]=='+') {
                sa[i]='-';
                sa[i+1]='-';
                results.add(new String(sa));
                sa[i]='+';
                sa[i+1]='+';
            }
        }
        return results;
    }
}