Clone an undirected graph. Each node in the graph contains a label
and a list of its
neighbors
.
OJ's undirected graph serialization:
Nodes are labeled uniquely.
We use#
as a separator for each node, and ,
as a separator for node label and each neighbor of the node.
As an example, consider the serialized graph {0,1,2#1,2#2,2}
.
The graph has a total of three nodes, and therefore contains three parts as separated by
#
.
- First node is labeled as
0
. Connect node0
to both nodes1
and2
. - Second node is labeled as
1
. Connect node1
to node2
. - Third node is labeled as
2
. Connect node2
to node2
(itself), thus forming a self-cycle.
Visually, the graph looks like the following:
1 / \ / \ 0 --- 2 / \ \_/
使用一个map,保存新图节点到原图的映射,
宽搜当前的图,将每一层的链接关系连接好
/**
* Definition for undirected graph.
* struct UndirectedGraphNode {
* int label;
* vector<UndirectedGraphNode *> neighbors;
* UndirectedGraphNode(int x) : label(x) {};
* };
*/
class Solution {
public:
UndirectedGraphNode *cloneGraph(UndirectedGraphNode *node) {
// Note: The Solution object is instantiated only once and is reused by each test case.
if(node == NULL) return NULL;
map<int,UndirectedGraphNode *> copy;
set<int> visited;
vector<UndirectedGraphNode *> next;
next.push_back(node);
copy[node->label] = new UndirectedGraphNode(node->label);
while(next.size() > 0) {
vector<UndirectedGraphNode *> pre;
for(int i = 0; i < next.size(); i++) {
UndirectedGraphNode *tmp = next[i];
if(copy.find(tmp->label) == copy.end()) copy[tmp->label] = new UndirectedGraphNode(tmp->label);
UndirectedGraphNode *copyNode = copy[tmp->label];
visited.insert(tmp->label);
vector<UndirectedGraphNode *> neigh =tmp->neighbors;
for(int i = 0; i < neigh.size(); i++) {
UndirectedGraphNode *t = neigh[i];
if(copy.find(t->label) == copy.end()) copy[t->label] = new UndirectedGraphNode(t->label);
copyNode->neighbors.push_back(copy[t->label]);
if(visited.count(t->label) == 0) {
visited.insert(t->label);
pre.push_back(t);
}
}
}
next.clear();
next.assign(pre.begin(),pre.end());
}
return copy[node->label];
}
};