[LeetCode]Reverse Words in a String

本文介绍了一种算法,用于将输入字符串中的单词顺序进行反转。通过使用堆栈数据结构,该算法可以有效地实现单词级别的反转,同时处理多个空格及前后空白字符。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >

Given an input string, reverse the string word by word.

For example,
Given s = "the sky is blue",
return "blue is sky the".

click to show clarification.

Clarification:

  • What constitutes a word?
    A sequence of non-space characters constitutes a word.
  • Could the input string contain leading or trailing spaces?
    Yes. However, your reversed string should not contain leading or trailing spaces.
  • How about multiple spaces between two words?
    Reduce them to a single space in the reversed string.
Answer:
class Solution {
public:
    void reverseWords(string &s) {
        if(!s.empty())
        {
            stack<string> sta;
            istringstream f(s);
            string str;
//            while(getline(f, str, ' '))
//            {
//               if (str > " ")
//                {
//                    sta.push(str);
//               }
//            }
            while(f >> str)
            {
              sta.push(str);
            }
            string temp = "";
            bool em = true;
            while (!sta.empty())
            {
                if (!em)
                {
                    temp += " ";
                }
                temp += sta.top();
                sta.pop();
                em = false;
            }
            s = temp;
        }
    }
};


评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值