PAT1091. Acute Stroke (30)

本文介绍了一种使用并查集算法计算MRI图像中急性脑卒中核心区域体积的方法。给定每片MRI切片的病灶区域,通过三维矩阵连接相邻像素,排除小于阈值的小病灶区,最终计算得出脑卒中核心体积。

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One important factor to identify acute stroke (急性脑卒中) is the volume of the stroke core. Given the results of image analysis in which the core regions are identified in each MRI slice, your job is to calculate the volume of the stroke core.

Input Specification:

Each input file contains one test case. For each case, the first line contains 4 positive integers: M, N, L and T, where M and N are the sizes of each slice (i.e. pixels of a slice are in an M by N matrix, and the maximum resolution is 1286 by 128); L (<=60) is the number of slices of a brain; and T is the integer threshold (i.e. if the volume of a connected core is less than T, then that core must not be counted).

Then L slices are given. Each slice is represented by an M by N matrix of 0’s and 1’s, where 1 represents a pixel of stroke, and 0 means normal. Since the thickness of a slice is a constant, we only have to count the number of 1’s to obtain the volume. However, there might be several separated core regions in a brain, and only those with their volumes no less than T are counted. Two pixels are “connected” and hence belong to the same region if they share a common side, as shown by Figure 1 where all the 6 red pixels are connected to the blue one.

这里写图片描述
Figure 1
Output Specification:

For each case, output in a line the total volume of the stroke core.

Sample Input:
3 4 5 2
1 1 1 1
1 1 1 1
1 1 1 1
0 0 1 1
0 0 1 1
0 0 1 1
1 0 1 1
0 1 0 0
0 0 0 0
1 0 1 1
0 0 0 0
0 0 0 0
0 0 0 1
0 0 0 1
1 0 0 0
Sample Output:
26

解题思路:用的是并查集,有点麻烦。
注意点:要将小的集合接到大的集合上,否则最后一个测点会超时。

AC代码:

#include<iostream>
using namespace std;

int m,n,l,t;
int ufs[85*1286*128];
bool slice[65][1300][135];

int gethead(int a)
{
    if(ufs[a] == a)
        return a;
    while(ufs[a] > 0)
        a = ufs[a];
    return a;
}

void unite(int a, int b)
{
    int ha = gethead(a);
    int hb = gethead(b);
    if(ha == hb)
        return;
    else if(ufs[a] == a&&ufs[b] == b)
    {
        ufs[a] = -2;
        ufs[b] = a;
    }
    else if(ufs[ha] < 0&&ufs[hb] < 0)
    {
        if(ufs[ha] < ufs[hb])
        {
            ufs[ha] += ufs[hb];
            ufs[hb] = ha;
        }
        else
        {
            ufs[hb] += ufs[ha];
            ufs[ha] = hb;
        }
    }
    else if(ufs[ha] < 0)
    {
        ufs[ha]--;
        ufs[hb] = ha;
    }
    else if(ufs[hb] < 0)
    {
        ufs[hb]--;
        ufs[ha] = hb;
    }
}
int main()
{   
    scanf("%d%d%d%d",&m,&n,&l,&t);
    for(int i = 1; i <= l; i++)
    {
        for(int j = 1; j <= m; j++)
        {
            for(int k = 1; k <= n; k++)
            {
                int temp;
                scanf("%d",&temp);
                slice[i][j][k] = temp;
            }
        }
    }
    int num = l * m * n;
    for(int i = 1; i <= num; i++)
        ufs[i] = i;
    for(int i = 1; i <= l; i++)
    {
        for(int j = 1; j <= m; j++)
        {
            for(int k = 1; k <= n; k++)
            {
                int temp = (i - 1) * m * n + (j - 1) * n + k;
                if(slice[i][j][k]==0)
                    continue;
                if(temp + m * n <= num&&slice[i + 1][j][k] != 0)
                    unite(temp,temp + m * n);
                if(temp + n <= num&&slice[i][j + 1][k] != 0)
                    unite(temp,temp + n);
                if(temp + 1 <= num&&slice[i][j][k + 1] != 0)
                    unite(temp,temp + 1);
                if(ufs[temp] == temp)
                    ufs[temp] = -1;
            }
        }
    }
    int sum = 0;
    for(int i = 1; i <= num; i++)
    {
        if(ufs[i] != i)
        {
            int tt = abs(ufs[gethead(i)]);
            if(tt >= t)
            {
                sum++; 
            }
        }
    }
    cout<<sum;
    return 0;
}
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