Construct Binary Tree from Inorder and Postorder Traversal

最新推荐文章于 2025-11-28 04:48:23 发布

最新推荐文章于 2025-11-28 04:48:23 发布 · 80 阅读

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本文介绍了一种根据中序和后序遍历构建二叉树的方法。通过递归地找到根节点，并利用中序遍历确定左右子树的范围，从而完成整棵树的构建。

Given inorder and postorder traversal of a tree, construct the binary tree.

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
public class Solution {
	public TreeNode buildTree(int[] inorder, int[] postorder) {
    	return buildTree(inorder, 0, inorder.length, postorder, 0, postorder.length);
    }

	private TreeNode buildTree(int[] inorder, int i, int length,
			int[] postorder, int j, int length2) {
		if (i>length-1 || j>length2-1) {
			return null;
		}
		int tmp = postorder[length2-1];
		int index = 0;
		for (int k = i; k < length; k++) {
			if (inorder[k] == tmp) {
				index = k;
				break;
			}
		}
		int len = index-i;
		TreeNode root = new TreeNode(tmp);
		root.left = buildTree(inorder, i, index, postorder, j, j+len);
		root.right = buildTree(inorder, index+1, length, postorder, j+len, length2-1);
		return root;
	}
}