Given a string containing only digits, restore it by returning all possible valid IP address combinations.
For example:
Given "25525511135",
return ["255.255.11.135", "255.255.111.35"]. (Order does not matter)
public class Solution {
public List<String> restoreIpAddresses(String s) {
List<String> res = new ArrayList<>();
String temp = new String();
if (s.length()<4 || s.length()>12) {
return res;
}
dfs(res, temp, 0, s);
return res;
}
private void dfs(List<String> res, String temp, int index, String s) {
if (index==3 && isValid(s)) {
res.add(temp+s);
return;
}
for (int i = 0; i<3 && i<s.length()-1; i++) {
String substring = s.substring(0, i+1);
if (isValid(substring)) {
dfs(res, temp+substring+'.', index+1, s.substring(i+1, s.length()));
}
}
}
private boolean isValid(String s) {
if (s.charAt(0) == '0') {
return s.equals("0");
}
int temp = Integer.parseInt(s);
if (temp<=255 && temp>0) {
return true;
} else {
return false;
}
}
}
本文介绍了一种通过递归深度优先搜索实现的算法,该算法能够将由纯数字组成的字符串恢复为所有可能的有效IP地址组合。例如,对于输入25525511135,算法能返回[255.255.11.135255.255.111.35]等有效IP地址。
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