Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.
For example,
Given 1->2->3->3->4->4->5, return 1->2->5.
Given 1->1->1->2->3, return 2->3.
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
public class Solution {
public ListNode deleteDuplicates(ListNode head) {
if (head == null) {
return head;
}
ListNode temp = new ListNode(0);
temp.next = head;
ListNode pre = temp;
ListNode cur = head;
ListNode nex = head.next;
boolean flag = false;
while (nex != null) {
if (cur.val == nex.val) {
flag = true;
nex = nex.next;
if (nex == null) {
pre.next = null;
}
} else {
if (flag) {
pre.next = nex;
flag = false;
} else {
pre = cur;
}
cur = nex;
nex = nex.next;
}
}
return temp.next;
}
}
422

被折叠的 条评论
为什么被折叠?



