Remove Duplicates from Sorted List

最新推荐文章于 2023-01-13 08:10:00 发布

最新推荐文章于 2023-01-13 08:10:00 发布 · 55 阅读

leetcode 专栏收录该内容

193 篇文章

订阅专栏

本文介绍了一种从已排序链表中删除所有重复元素的方法，确保每个元素仅出现一次。通过遍历链表并比较相邻节点值来实现，若发现重复则跳过重复节点，最终返回处理后的链表。

Given a sorted linked list, delete all duplicates such that each element appear only once.

For example,
Given 1->1->2, return 1->2.
Given 1->1->2->3->3, return 1->2->3.

/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) { val = x; }
 * }
 */
public class Solution {
    public ListNode deleteDuplicates(ListNode head) {
    	if (head == null) {
    		return head;
    	}
    	ListNode start = head;
    	ListNode end = head.next;
    	while (end != null) {
    		if (start.val == end.val) {
    			end = end.next;
    			if (end == null) {
    				start.next = null;
    			}
    		} else {
    			start.next = end;
    			start = start.next;
    			end = end.next;
    		}
    	}
    	return head;
    }
}