Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses.
For example, given n = 3, a solution set is:
"((()))", "(()())", "(())()", "()(())", "()()()"
public class Solution {
public List<String> generateParenthesis(int n) {
List<String> list = new ArrayList<String>();
solve(n,0,0,"",list);
return list;
}
private void solve(int n, int left, int right, String string, List<String> list) {
if (left==n && right==n) {
list.add(string);
}
if (left < n) {
solve(n,left+1,right,string+'(',list);
}
if (right<n && left>right) {
solve(n,left,right+1,string+')',list);
}
}
}
本文提供了一个函数,用于生成给定数量的括号对的所有合法组合,例如当n为3时,组合包括((()))
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