Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
public class Solution {
public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
if (l1 == null) {
return l2;
}
if (l2 == null) {
return l1;
}
ListNode head, tail;
if (l1.val < l2.val) {
head = tail = l1;
l1 = l1.next;
} else {
head = tail = l2;
l2 = l2.next;
}
while (l1!=null && l2!=null) {
if (l1.val < l2.val) {
tail.next = l1;
tail = l1;
l1 = l1.next;
} else {
tail.next = l2;
tail = l2;
l2 = l2.next;
}
}
tail.next = (l1==null)?l2:l1;
return head;
}
}
class Solution {
public:
ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) {
if (l1 == NULL) {
return l2;
}
if (l2 == NULL) {
return l1;
}
ListNode* head;
ListNode* tail;
if (l1->val < l2->val) {
head = tail = l1;
l1 = l1->next;
} else {
head = tail = l2;
l2 = l2->next;
}
while (l1!=NULL && l2!=NULL) {
if (l1->val < l2->val) {
tail->next = l1;
tail = l1;
l1 = l1->next;
} else {
tail->next = l2;
tail = l2;
l2 = l2->next;
}
}
tail->next = (l1==NULL)?l2:l1;
return head;
}
};
1470

被折叠的 条评论
为什么被折叠?



